Want to contribute?

Create stuff with entries for architects and buildings?
--
Edit stuff with updates on existing entries using Architectuul's icon.

Dive straight in

If so, register, only e-mail and username required
--

Already a member?

Then login here.

(default) 6 queries took 46 ms
NrQueryErrorAffectedNum. rowsTook (ms)
1SELECT `Role`.`name`, `Role`.`permissions` FROM `roles` AS `Role` WHERE 1 = 1 552
2SELECT `User`.`id`, `User`.`username`, `User`.`slug`, `User`.`fname`, `User`.`lname`, `User`.`verified`, `User`.`top_list_count`, `User`.`comment_count`, `User`.`old_id`, `User`.`created`, `User`.`modified`, `User`.`name`, `User`.`password`, `User`.`password_hash_version`, `User`.`old_password_hash`, `User`.`role_id`, `User`.`login`, `User`.`active`, `User`.`gender`, `User`.`profile_visit_count`, `User`.`country_id`, `User`.`state_id`, `User`.`background`, `User`.`profession`, `User`.`photo_url`, `User`.`sm_photo_url`, `User`.`architecture_count`, `User`.`architect_count`, `User`.`activation_reminded`, `User`.`website`, `User`.`facebook`, `User`.`twitter`, `User`.`archived`, `User`.`last_login`, `User`.`cancelled`, `User`.`comment_notification`, `User`.`watch_notification`, `User`.`collection_notification`, `Role`.`id`, `Role`.`name`, `Role`.`permissions`, `Role`.`description`, `Role`.`created`, `Role`.`modified` FROM `users` AS `User` LEFT JOIN `roles` AS `Role` ON (`User`.`role_id` = `Role`.`id`) WHERE `login` = 'guest@architectuul.com' LIMIT 11124
3SELECT COUNT(*) AS `count` FROM `users` AS `User` WHERE `User`.`id` = '7e59ae88-ffa7-11de-b287-4f8fe1b9fcc1' 112
4SELECT COUNT(*) AS `count` FROM `users` AS `User` WHERE `User`.`id` = '7e59ae88-ffa7-11de-b287-4f8fe1b9fcc1' 112
5UPDATE `users` SET `id` = '7e59ae88-ffa7-11de-b287-4f8fe1b9fcc1', `last_login` = '2019-08-20 04:07:28', `modified` = '2019-08-20 04:07:28' WHERE `users`.`id` = '7e59ae88-ffa7-11de-b287-4f8fe1b9fcc1'03
6SELECT `Architecture`.`title`, `Architecture`.`slug` FROM `architectures` AS `Architecture` WHERE `Architecture`.`deleted` <> 1 ORDER BY Rand() ASC LIMIT 11113